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Helpmedu69
@Helpmedu69
April 2019
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Pouvez vous m aider resoudre
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√(x²+y²+1)=√(-x²-y²+1) pour (x,y) différent de (1,0) et (0,1)
x²+y²+1=-x²-y²+1
2x²+2y²=0
x²+y²=0
(x,y)=(0,0)
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c extremement urgentJ ai donc 1,600 g de carbonate de sodium (Na2CO3) et de l'eau distile (H2O) qui me fait une solution de 100 ml a 10-1 mol/L Ma question est ecrire la reaction de dissolutionEt quelle la concentration de chacun des ions present dans la solution
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bonjour c est extremement urgent aider moi a fair la derniere question ecrite main le tout bien entendu en espagnol merci d avancevous trouverez deux image si join
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x²+y²+1=-x²-y²+1
2x²+2y²=0
x²+y²=0
(x,y)=(0,0)