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Luciefourgous
@Luciefourgous
May 2019
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Pouvez-vous m'aider à résoudre ce problème s'il vous plaît c'est assez urgent je donne 20 points. Merci d'avance
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anonymus7587
On a :
DC = EC-ED = 3y-11
AB = ED = BC = 11
AE = BD = y
D'après Pythagore :
BD² = BC²-DC²
y² = 11²-(3y-11)²
y²-11²-(3y-11)² = 0
y²-112+9y²-66y+112
= 0
10y²
-66y=0
y² = 66y/10
y = 6,6
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DC = EC-ED = 3y-11
AB = ED = BC = 11
AE = BD = y
D'après Pythagore :
BD² = BC²-DC²
y² = 11²-(3y-11)²
y²-11²-(3y-11)² = 0
y²-112+9y²-66y+112 = 0
10y²-66y=0
y² = 66y/10
y = 6,6