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Luciefourgous
@Luciefourgous
May 2019
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Pouvez-vous m'aider à résoudre ce problème s'il vous plaît c'est assez urgent je donne 20 points. merci d'avance
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trudelmichel
Verified answer
Bonjour
dans le triangle rectangle BDC
BC²=BD²+DC²
DC=3y-11 DC²= (3y-11)²=9y²-66y+121
BD=y BD²=y²
BC=11 BC²=121
121=y²+9y²-66y+121
10y²-66y=0
y(10y-66)=0
soit y=0 impossible
10y-66=0
10y=66
y=6.6
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Verified answer
Bonjourdans le triangle rectangle BDC
BC²=BD²+DC²
DC=3y-11 DC²= (3y-11)²=9y²-66y+121
BD=y BD²=y²
BC=11 BC²=121
121=y²+9y²-66y+121
10y²-66y=0
y(10y-66)=0
soit y=0 impossible
10y-66=0
10y=66
y=6.6