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lacrima95
@lacrima95
January 2021
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Pouvez vous m'aidez pour l'exercice 17 svpp
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Miss54680
1) le moteur est traversé par un courant de 520mA 5 (soit 0.52 A) car il est sur la meme branche que l'ampermètre.
2)D'apres la loi des noeuds,l'intensité du courant traversant l3 vaut 0.22 A.
0.74-0.52 = 0.22 A
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Thanks 1
lacrima95
Dacc merci
Miss54680
DERIEN
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2)D'apres la loi des noeuds,l'intensité du courant traversant l3 vaut 0.22 A.
0.74-0.52 = 0.22 A