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@Mimiii59209p3u7ws
May 2019
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Pouvez-vous vous m’aider svp merci d’avance mon exercice est pour demain
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taalbabachir
Verified answer
Cos (BDC) = 5.5/6 = 0.91666 ⇒ BDC = 23.56°
tan (BDA) = 5/6 = 0.83333 ⇒ BDA = 39.80°
l'angle ADC = BDC + BDA = 23.56 + 39.8 = 63.36° soit ADC ≈ 63.4°
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Verified answer
Cos (BDC) = 5.5/6 = 0.91666 ⇒ BDC = 23.56°tan (BDA) = 5/6 = 0.83333 ⇒ BDA = 39.80°
l'angle ADC = BDC + BDA = 23.56 + 39.8 = 63.36° soit ADC ≈ 63.4°