[tex]\displaystyle \sf \frac{\ln a^3-\log a+2\ln a }{\log a} \\\\\\ \frac{3\ln a -\log a +2\ln a}{\log a } \\\\\\ \frac{5\ln a -\log a }{\log a}\\\\\\ \frac{5\ln a}{\log a}-\frac{\log a}{\log a} \\\\\\\ \boxed{\sf obs: \log a= \frac{\ln a}{\ln 10}} \\\\\\ \frac{5\ln a}{\displaystyle \frac{\ln a}{\ln 10}} - 1 \\\\\\ 5\not \ln a \cdot \frac{\ln 10}{\not \ln a } - 1 \\\\\\\ 5\cdot \ln 10 - 1 \\\\ 5\cdot 2,3-1 \\\\\ 11,5-1 = 10,5[/tex]

[tex]\displaystyle \sf portanto : \\\\ \large\boxed{\sf \ \frac{\ln a^3-\log a+2\ln a }{\log a} = 10,5 \ }\checkmark[/tex]

letra B