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TeoBrt
@TeoBrt
May 2019
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Quelqu’un pourrai m’aider svp ? Merci d’avance !
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Bonsoir
f(x) = ( x - 7)² - 9
1) f(x) = x² - 14 x + 49 - 9 =
x² - 14 x + 40
2) f(x) = ( x - 7 - 3) ( x - 7 + 3) =
( x - 10) ( x - 4 )
3) f(0) = -10 * - 4 =
40
f(7) = - 3 * 3 =
- 9
4) antécédents de 0 =
10 et 4
5) f(x) = 40
(x - 7)² - 9 = 40
( x - 7 )² = 40 + 9
(x - 7)² = 49
x - 7 = √49
x - 7 = 7
x = 14
6) (x - 7)² - 9 = - 10
(x - 7)² = - 10 + 9
'x - 7)² = - 1 ⇔ pas de solution , un carré ne peut pas être négatif
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f(x) = ( x - 7)² - 9
1) f(x) = x² - 14 x + 49 - 9 = x² - 14 x + 40
2) f(x) = ( x - 7 - 3) ( x - 7 + 3) = ( x - 10) ( x - 4 )
3) f(0) = -10 * - 4 = 40
f(7) = - 3 * 3 = - 9
4) antécédents de 0 = 10 et 4
5) f(x) = 40
(x - 7)² - 9 = 40
( x - 7 )² = 40 + 9
(x - 7)² = 49
x - 7 = √49
x - 7 = 7
x = 14
6) (x - 7)² - 9 = - 10
(x - 7)² = - 10 + 9
'x - 7)² = - 1 ⇔ pas de solution , un carré ne peut pas être négatif