(Questão 03)
*
Imagem sem legenda
y=-1.12x-0.64
y=0.64x+1.12
y=-0.64x-1.12
y=x-0.64
y=0.64x-1.12
y=-1.12x+1
y=1.12x+2
y=-x+0.64
y=0.64x+2
*
Imagem sem legenda
y=-1.12x-0.64
y=0.64x+1.12
y=-0.64x-1.12
y=x-0.64
y=0.64x-1.12
y=-1.12x+1
y=1.12x+2
y=-x+0.64
y=0.64x+2
More Questions From This User See All