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matheusg30
@matheusg30
April 2022
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RELAÇAO METRICA DO TRIANGULO RETANGULO Hiponetusa mede 28cm Cateto "b" mede 21cm calcular o valor do cateto "c" quanto mede "m " quanto mede"n" quanto mede a altura
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AltairAlves
Verified answer
Hipotenusa = a
Aplicando Pitágoras:
a² = b² + c²
28² = 21² + c²
784 = 441 + c²
c² = 784 - 441
c² = 343
c = √343
c ≈ 18,52 cm
Valor de m:
c² = m.a
343 = m . 28
m = 343/28
m = 12,25 cm
Valor de n:
b² = n.a
21² = n . 28
441 = n . 28
n = 441/28
n = 15,75 cm
Valor de h:
h² = m.n
h² = 12,25 . 15,75
h² = 192,9375
h = √192,9375
h ≈ 13,90 cm
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Verified answer
Hipotenusa = aAplicando Pitágoras:
a² = b² + c²
28² = 21² + c²
784 = 441 + c²
c² = 784 - 441
c² = 343
c = √343
c ≈ 18,52 cm
Valor de m:
c² = m.a
343 = m . 28
m = 343/28
m = 12,25 cm
Valor de n:
b² = n.a
21² = n . 28
441 = n . 28
n = 441/28
n = 15,75 cm
Valor de h:
h² = m.n
h² = 12,25 . 15,75
h² = 192,9375
h = √192,9375
h ≈ 13,90 cm