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Alvite
@Alvite
April 2019
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Si quelqu'un pourrait m'aider, je suis un peu embeter
E(x)= 4x^{2} -9- (x-5)(2x -3)
1/Développer et réduire.
2/Factoriser 4x^ {2}-9 ; en déduire la factorisation de E(x)
3/ Résoudre E(x) = 0
4/ Résoudre E(x) = - 24
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laurance
1)4x²-9 -2x² +3x+10x-15 = 2x² +13x -24
2)(2x+3)(2x-3) et E(x)=(2x-3)((2x+3)-(x-5)) =(2x-3)(2x+3-x+5)= (2x-3)(x+8)
3)E(x)=0 si 2x-3=0 ou x+8=0 x = 3/2 ou x = - 8
4)E(x)=-24 si 2x² +13x -24 = -24 2x² + 13x = 0 x(2x+13)=0
x=0 ou 2x+13=0 x=0 ou x= -13/2
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2)(2x+3)(2x-3) et E(x)=(2x-3)((2x+3)-(x-5)) =(2x-3)(2x+3-x+5)= (2x-3)(x+8)
3)E(x)=0 si 2x-3=0 ou x+8=0 x = 3/2 ou x = - 8
4)E(x)=-24 si 2x² +13x -24 = -24 2x² + 13x = 0 x(2x+13)=0
x=0 ou 2x+13=0 x=0 ou x= -13/2