Bjr
x² + 2x - 15
discriminant = b² - 4ac = 2² - 4 * 1 * - 15 = 4 + 60 = 64
x1 = (- 2 + 8)/(2 * 1) = 6/2 = 3
x2 = (-2 - 8)/(2 * 1) = -10/2 = -5
donc x² + 2x - 15 = (x - 3)(x + 5)
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Bjr
x² + 2x - 15
discriminant = b² - 4ac = 2² - 4 * 1 * - 15 = 4 + 60 = 64
x1 = (- 2 + 8)/(2 * 1) = 6/2 = 3
x2 = (-2 - 8)/(2 * 1) = -10/2 = -5
donc x² + 2x - 15 = (x - 3)(x + 5)