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Halimatraore30
@Halimatraore30
April 2019
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Salut s'il vous plait au secoue E= (x-3)²+(x-3)(1-2x)ou x désigne un nombre. a.développer et réduire E b.prouver que l'expression factorisée de E EST (5X-3) (-x-2) c.résoudre l’équation E=0
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Bonjour
Halimatraore30
E = (x - 3)² + (x - 3)(1 - 2x)
a) Développer et réduire.
E = (x - 3)² + (x - 3)(1 - 2x)
E = (x² - 6x + 9) + (x - 2x² - 3 + 6x)
E = x² - 6x + 9 + x - 2x² - 3 + 6x
E = -x² + x + 6
b) Factorisation.
E = (x - 3)² + (x - 3)(1 - 2x)
E = (x - 3)(x - 3) + (x - 3)(1 - 2x)
E = (x - 3)[(x - 3) + (1 - 2x)]
E = (x - 3)(x - 3 + 1 - 2x)
E = (x - 3)(-x - 2)
c) Résoudre l'équation E = 0
E = 0
(x - 3)(-x - 2) = 0
x - 3 = 0 ou -x - 2 = 0
x = 3 ou -x = 2
x = 3 ou x = -2
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E = (x - 3)² + (x - 3)(1 - 2x)
a) Développer et réduire.
E = (x - 3)² + (x - 3)(1 - 2x)
E = (x² - 6x + 9) + (x - 2x² - 3 + 6x)
E = x² - 6x + 9 + x - 2x² - 3 + 6x
E = -x² + x + 6
b) Factorisation.
E = (x - 3)² + (x - 3)(1 - 2x)
E = (x - 3)(x - 3) + (x - 3)(1 - 2x)
E = (x - 3)[(x - 3) + (1 - 2x)]
E = (x - 3)(x - 3 + 1 - 2x)
E = (x - 3)(-x - 2)
c) Résoudre l'équation E = 0
E = 0
(x - 3)(-x - 2) = 0
x - 3 = 0 ou -x - 2 = 0
x = 3 ou -x = 2
x = 3 ou x = -2