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@izabellly
July 2022
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sejam as retas (r)3x-4y+6=0 e (s) = ax-8. Para quais valores a de a essas retas são concorrentes e não perpendiculares? [Assunto:Noções sobre retas]
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jhullynhacosta
3x - 4y + 6 = 0
- 4y = - 3x - 6
4y = 3x + 6
y = 3x + 6 / 4
a.(3/4) = - 1
3a = - 4
a = - 4 / 3
-------------------------- > a =/= ( - 4/3 )
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- 4y = - 3x - 6
4y = 3x + 6
y = 3x + 6 / 4
a.(3/4) = - 1
3a = - 4
a = - 4 / 3
-------------------------- > a =/= ( - 4/3 )