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Slngttn
@Slngttn
April 2019
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Soit l'expression : A = (x) = (3x + 7)² - (5x - 4)(3x +7)
a. Développer et réduire A(x).
b. Factoriser A(x)
c. Résoudre : A(x) = 0.
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anylor
A)
A (x) = (3x + 7)² - (5x - 4)(3x +7)a)
9x² +42 x +49 - (15x² +35x -12x -28) =
9x² +42 x +49 - 15x² -35x + 12x +28 =
- 6x² + 19x + 77
b)
facteur commun (3x +7)
(3x+7) [ (3x +7 - (5x -4) ] =
(3x+7) (3x +7 - 5x +4) =
(3x+7) (-2 x +11)
c) un produit de facteurs est nul, si au moins l'un des ses facteurs est nul
3x+7 = 0 => x = -7/3
-2 x +11 = 0 => x = 11/2
S= { -7/3 ; 11 /2}
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A (x) = (3x + 7)² - (5x - 4)(3x +7)a)
9x² +42 x +49 - (15x² +35x -12x -28) =
9x² +42 x +49 - 15x² -35x + 12x +28 =
- 6x² + 19x + 77
b)
facteur commun (3x +7)
(3x+7) [ (3x +7 - (5x -4) ] =
(3x+7) (3x +7 - 5x +4) =
(3x+7) (-2 x +11)
c) un produit de facteurs est nul, si au moins l'un des ses facteurs est nul
3x+7 = 0 => x = -7/3
-2 x +11 = 0 => x = 11/2
S= { -7/3 ; 11 /2}