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Higgy
@Higgy
June 2021
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svp aider moi!!!! c'est urgent c'est pour demain merci
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slyz007
Verified answer
Une fonction affine est de la forme f(x)=ax+b
f(2)=√2 soit 2a+b=√2 donc b=√2-2a
f(-2)=1/3 donc 1/3=-2a+b=-2a+√2-2a
Donc 4a=√2-1/3 soit a=(3√2-1)/12 et b=(3√2+1)/6
f(x)=(3√2-1)/12*x+(3√2+1)/6
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Thanks 1
Higgy
merci
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Verified answer
Une fonction affine est de la forme f(x)=ax+bf(2)=√2 soit 2a+b=√2 donc b=√2-2a
f(-2)=1/3 donc 1/3=-2a+b=-2a+√2-2a
Donc 4a=√2-1/3 soit a=(3√2-1)/12 et b=(3√2+1)/6
f(x)=(3√2-1)/12*x+(3√2+1)/6