Articles
Register
Sign In
Search
Gerbillemandu69
@Gerbillemandu69
April 2019
2
85
Report
SVP aider moi je dois ptit DM en math
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
jakecoolin
Verified answer
Expression (2*x-1)^2-16 = (2*x-5)*(2*x+3)
(2x−5)
(2x+3)
0 votes
Thanks 1
gerbillemandu69
merci
ficanas06
(2x-1)² -16 est du type a²-b²=(a-b)(a+b) identité remarquable
(2x-1)² -16 =(2x-1-4)(2x-1+4)=
(2x-5)(2x+3)
0 votes
Thanks 1
gerbillemandu69
merci
More Questions From This User
See All
gerbillemandu69
June 2021 | 0 Respostas
Bonjour a tous je dois rendre un devoir de math pour lundi besoin d'aide urgent merci d'avance
Responda
gerbillemandu69
June 2021 | 0 Respostas
Responda
gerbillemandu69
January 2021 | 0 Respostas
Bonsoir j'aurais besoin d'aide pour un DM de math merci
Responda
Gerbillemandu69
April 2019 | 0 Respostas
D.M URGENT SVP !!!!! IL N'YA QUE 1 EXO
Responda
Gerbillemandu69
April 2019 | 0 Respostas
Bonjour svp D.M de math a rendre pour demain il ya un exercice
Responda
Gerbillemandu69
April 2019 | 0 Respostas
URGENT DM POUR DEMAIN COEF2 SUJET EN PIECE JOINTE MERCI D'AVANCE
Responda
Gerbillemandu69
April 2019 | 0 Respostas
Re SVP DM de math a rendre pour demain pas long
Responda
Gerbillemandu69
April 2019 | 0 Respostas
Responda
Gerbillemandu69
April 2019 | 0 Respostas
Responda
Gerbillemandu69
April 2019 | 0 Respostas
Responda
×
Report "SVP aider moi je dois ptit DM en math.... Pergunta de ideia de Gerbillemandu69"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
Verified answer
Expression (2*x-1)^2-16 = (2*x-5)*(2*x+3)(2x−5)(2x+3)(2x-1)² -16 =(2x-1-4)(2x-1+4)= (2x-5)(2x+3)