(2x-5)(x+3)+(4x-10)(x-1)
= (2x-5)(x+3)+2(2x-5)(x-1)
= (2x-5)[(x+3) + 2(x-1)]
= (2x-5) (3x+1)
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(2x-5)(x+3)+(4x-10)(x-1)
= (2x-5)(x+3)+2(2x-5)(x-1)
= (2x-5)[(x+3) + 2(x-1)]
= (2x-5) (3x+1)