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Leasa
@Leasa
April 2019
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SVP c urgent il faut factoriser
(x+1)^2-4=0
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meemameema
Verified answer
(x + 1)² - 4 = 0
(x + 1)² - 2² = 0
(x + 1 + 2)(x + 1 - 2) = 0
(x + 3)(x - 1) = 0 un produit de facteurs est nul si l'un des facteur est nul
x +3 = 0 ⇒
x = - 3
x - 1 = 0 ⇒
x = 1
les solutions de l'équation sont - 3 et 1
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Lista de comentários
Verified answer
(x + 1)² - 4 = 0(x + 1)² - 2² = 0
(x + 1 + 2)(x + 1 - 2) = 0
(x + 3)(x - 1) = 0 un produit de facteurs est nul si l'un des facteur est nul
x +3 = 0 ⇒ x = - 3
x - 1 = 0 ⇒ x = 1
les solutions de l'équation sont - 3 et 1