(2x+1)(x+3)-(2x+1)(5x+1)<0
(2x+1)(x+3-5x-1)<0
(2x+1)(-4x+2)<0
(2x+1)<0 ou (-4x+2)<0
2x<-1 ou -4x<-2
x<-1/2 ou x>1/2
Ainsi, (2x+1)(x+3)-(2x+1)(5x+1)<0 quand x∈]-∞;-1/2[∪]1/2;+∞[
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(2x+1)(x+3)-(2x+1)(5x+1)<0
(2x+1)(x+3-5x-1)<0
(2x+1)(-4x+2)<0
(2x+1)<0 ou (-4x+2)<0
2x<-1 ou -4x<-2
x<-1/2 ou x>1/2
Ainsi, (2x+1)(x+3)-(2x+1)(5x+1)<0 quand x∈]-∞;-1/2[∪]1/2;+∞[