Svpp vraiment besoin d'aide je vois en supplie.... Pergunta de ideia de03cecelol

03cecelol @03cecelol

May 2019 1 63 Report

Svpp vraiment besoin d'aide je vois en supplie

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Bonjour,

a) aCh = aCb
   aHc = bAc = 90°
⇒les 2 triangles sont semblables ( justifie avec les propriétés qui font que 2 triangles sont semblables)

b) HA/AB = HC/AC=AC/BC

c) HC/AC=AC/BC
   HC/2 = 2/5
   HC = 2*2/5 = 0,8

d) A BAC = AC*AB/2
   AB² = 5²-4 = 21
   AB = √21
   A bAC = 2*√21/2 = 2√21/2 = 2√21/2

l'aire est aussi BC*AH/2
2√21/2 = 5*AH/2
AH = 4√21/10

hors √336/√100 = 4√21/10

en simplifiant 4√21/10 = AH = 2√21/5

e) avec pythagore ds BAC ( déjà calculé d)

ds AHC :
AB² = AH²+HB²
   = (2√21/5)² + 4,2²
   = 84/25+441/25
AB = √21

2 votes Thanks 1

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