Verified answer

Resposta passo a passo:

[tex]a)3^{3} =3\times3\times3=9\times3=27[/tex]

[tex]b)(\frac{1}{3} )^{3} =\frac{1^{3} }{3^{3} } =\frac{1\times1\times1}{3\times3\times3} =\frac{1}{9\times3} =\frac{1}{27}[/tex]

[tex]c)4^{0} =4^{1-1} =\frac{4^{1} }{4^{1} } =\frac{4}{4} =1[/tex]

[tex]d)(-5)^{2} =(-5)\times(-5)=25[/tex]

[tex]e)(-\frac{1}{5} )^{3} =(\frac{-1}{5} )^{3}=\frac{-1\times(-1)\times(-1)}{5\times5\times5}=\frac{1\times(-1)}{25\times5} =\frac{-1}{125} =-\frac{1}{125}[/tex]

[tex]f)(-7)^{3} =(-7)\times(-7)\times(-7)=49\times(-7)=-343[/tex]