calcular a integral [tex] \int[/tex] (x³-6x²+4x-2) dx.... Pergunta de ideia depalomaalves05

palomaalves05 @palomaalves05

March 2022 1 43 Report

calcular a integral [tex] \int[/tex] (x³-6x²+4x-2) dx

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Olá, Paloma.

$\int x\³-6x\²+4x-2\ dx=\\\\=\frac{x^4}4-6\cdot\frac{x^3}3+4\cdot\frac{x^2}2-2x=\\\\=\frac{x^4}4-2x^3+2x^2-2x$

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