Calcule a) [tex] \lim_{x \to \01} ( 2x^{4} + 2x^{3} + x - 3 ) [/tex] b) [tex] \lim_{x \to \05} \fra.... Pergunta de ideia degessinara

April 2022 1 51 Report

Calcule
a) [tex] \lim_{x \to \01} ( 2x^{4} + 2x^{3} + x - 3 ) [/tex]

b) [tex] \lim_{x \to \05} \frac{x^{2} - 25}{x-5} [/tex]

c) [tex] \lim_{x \to \00} \frac{ x^{4}+ x^{3} - x^{2} + 1 }{ x^{2} +1} [/tex]

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dcarvalho1991 A)
$\lim_{x \to 1} 2x^{4} + 2x^{3} + x - 3 = \\ = 2. 1^{4} + 2. 1^{3} + 1 - 3 = 2 + 2 - 2 = 2$
b)
$\lim_{x \to 5} \frac{ x^{2} - 25}{x - 5} = \lim_{x \to 5} \frac{(x - 5)(x + 5)}{x - 5} = \\ 
= \lim_{x \to 5} x + 5 = 5 + 5 = 10$
c)
$\lim_{x \to 0} \frac{ x^{4} + x^{3} - x^{2} +1}{ x^{2} + 1} = \\ \frac{ 0^{4} + 0^{3} - 0^{2} + 1}{ 0^{2} +1 } = \\ 
 \frac{1}{1} = 1$

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Calcule a) [tex] \lim_{x \to \01} ( 2x^{4} + 2x^{3} + x - 3 ) [/tex] b) [tex] \lim_{x \to \05} \frac{x^{2} - 25}{x-5} [/tex] c) [tex] \lim_{x \to \00} \frac{ x^{4}+ x^{3} - x^{2} + 1 }{ x^{2} +1} [/tex]

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Calcule a) [tex] \lim_{x \to \01} ( 2x^{4} + 2x^{3} + x - 3 ) [/tex] b) [tex] \lim_{x \to \05} \frac{x^{2} - 25}{x-5} [/tex] c) [tex] \lim_{x \to \00} \frac{ x^{4}+ x^{3} - x^{2} + 1 }{ x^{2} +1} [/tex]

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