Calcule a) [tex] \lim_{x \to \01} ( 2x^{4} + 2x^{3} + x - 3 ) [/tex] b) [tex] \lim_{x \to \05} \fra.... Pergunta de ideia degessinara

April 2022 1 38 Report

Calcule
a) [tex] \lim_{x \to \01} ( 2x^{4} + 2x^{3} + x - 3 ) [/tex]

b) [tex] \lim_{x \to \05} \frac{x^{2} - 25}{x-5} [/tex]

c) [tex] \lim_{x \to \00} \frac{ x^{4}+ x^{3} - x^{2} + 1 }{ x^{2} +1} [/tex]

Lista de comentários

pernia Olá
Resolvendo temos:
$\lim_{x \to } _{1} (2 x^{4}+2 x^{3}+ x-3) \\ \\ x=1 \\ (2 (1^{4} )+2( 1^{3} )+1-3 \\ 2+2+1-3 \\ =2$

b)

$\lim_{x \to \ 5 \frac{ x^{2} -25}{x-5} = \frac{ x^{2} - 5^{2} }{x-5} = \frac{(x-5)(x+5)}{x-5}$

cortamos (x-5)

$(x+5)-------->x=5
5+5=10....resposta.$

c)

$\lim_{x \to \ o \frac{ x^{4}+ x^{3}- x^{2} +1 }{ x^{2} +1}$

x=0

$\frac{ 0^{4}+ 0^{3}- 0^{2} +1 }{ 0^{2}+1 }= \frac{1}{1} =1$

2 votes Thanks 1

Calcule a) [tex] \lim_{x \to \01} ( 2x^{4} + 2x^{3} + x - 3 ) [/tex] b) [tex] \lim_{x \to \05} \frac{x^{2} - 25}{x-5} [/tex] c) [tex] \lim_{x \to \00} \frac{ x^{4}+ x^{3} - x^{2} + 1 }{ x^{2} +1} [/tex]

Responda

gessinara April 2022 | 0 Respostas

Responda

gessinara April 2022 | 0 Respostas

Responda

gessinara April 2022 | 0 Respostas

Responda

gessinara March 2022 | 0 Respostas

Responda

gessinara March 2022 | 0 Respostas

Responda

Lista de comentários

Calcule a) [tex] \lim_{x \to \01} ( 2x^{4} + 2x^{3} + x - 3 ) [/tex] b) [tex] \lim_{x \to \05} \frac{x^{2} - 25}{x-5} [/tex] c) [tex] \lim_{x \to \00} \frac{ x^{4}+ x^{3} - x^{2} + 1 }{ x^{2} +1} [/tex]

Helpful Links

Helpful Social