Resolva as seguintes equações,com a formula de Bhaskara.
a)[tex] x^{2} -12x+36=0[/tex]
b)[tex] x^{2} +4x+4=0[/tex]
a)[tex] x^{2} -12x+36=0[/tex]
b)[tex] x^{2} +4x+4=0[/tex]
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Δ = -122 - 4 . 1 . 36
Δ = 144 - 4. 1 . 36
Δ = 0
Há 1 raiz real.
Neste caso, x' = x'':
x = (-b +- √Δ)/2a
x' = (--12 + √0)/2.1
x'' = (--12 - √0)/2.1
x' = 12 / 2
x'' = 12 / 2
x' = 6
x'' = 6
B) Δ = b2 - 4.a.c
Δ = 42 - 4 . 1 . 4
Δ = 16 - 4. 1 . 4
Δ = 0
Há 1 raiz real.
Neste caso, x' = x'':
x = (-b +- √Δ)/2a
x' = (-4 + √0)/2.1
x'' = (-4 - √0)/2.1
x' = -4 / 2
x'' = -4 / 2
x' = -2
x'' = -2