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nycoleboop
@nycoleboop
August 2022
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Resolva a seguinte equação,com a formula de Bhaskara.
a)[tex] x^{2} -8x+15=0[/tex]
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PauloLuis
Δ = b2
- 4.a.c
Δ = -82
- 4 . 1 . 15
Δ = 64 - 4. 1 . 15
Δ = 4
Há 2 raízes reais.
x = (-b +- √Δ)/2a
x' = (--8 + √4)/2.1
x'' = (--8 - √4)/2.1
x' = 10 / 2
x'' = 6 / 2
x' = 5
x'' = 3
1 votes
Thanks 1
nathinha6799
X^2-8x+15=0
delta=b^2-4ac
delta=(-8)^2-4.1.15
delta=64-60
delta=4
x=-b-/+ raiz de delta/2a
x=-(-8)-2/2.1
x=8-2/2
x=6/2
x=3
x=-(-8)+2/2.1
x=8+2/2
x=10/2
x=5
0 votes
Thanks 1
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Δ = -82 - 4 . 1 . 15
Δ = 64 - 4. 1 . 15
Δ = 4
Há 2 raízes reais.
x = (-b +- √Δ)/2a
x' = (--8 + √4)/2.1
x'' = (--8 - √4)/2.1
x' = 10 / 2
x'' = 6 / 2
x' = 5
x'' = 3
delta=b^2-4ac
delta=(-8)^2-4.1.15
delta=64-60
delta=4
x=-b-/+ raiz de delta/2a
x=-(-8)-2/2.1
x=8-2/2
x=6/2
x=3
x=-(-8)+2/2.1
x=8+2/2
x=10/2
x=5