Transforme em produto as expressões:a) sen (2x + y) + sen (2x - y)b) cos (a+b+c) + cos (a+b-c).... Pergunta de ideia dejhenniferfga

March 2022 1 32 Report

Transforme em produto as expressões:
a) sen (2x + y) + sen (2x - y)
b) cos (a+b+c) + cos (a+b-c)

Lista de comentários

Niiya

Verified answer

$sen~p+sen~q=2*sen~\left(\dfrac{p+q}{2}\right)*cos~\left(\dfrac{p-q}{2}\right)\\\\\\cos~p+cos~q=2*cos~\left(\dfrac{p+q}{2}\right)*cos~\left(\dfrac{p-q}{2}\right)$
_____________________________

a)

$sen~(2x+y)+sen~(2x-y)=2\cdot sen~(\frac{2x+y+2x-y}{2})\cdot cos~(\frac{2x+y-(2x-y)}{2})\\\\sen~(2x+y)+sen~(2x-y)=2\cdot sen~(\frac{4x}{2})\cdot cos~(\frac{2y}{2})\\\\\boxed{\boxed{sen~(2x+y)+sen~(2x-y)=2\cdot sen~(2x)\cdot cos~y}}$

b)

$cos~(a+b+c)+cos~(a+b-c)=cos~([a+b]+c)+cos~([a+b]-c)\\\\cos~(a+b+c)+cos~(a+b-c)=2\cdot cos~(\frac{a+b+c+a+b-c}{2})\cdot cos~(\frac{a+b+c-(a+b-c)}{2})\\\\cos~(a+b+c)+cos~(a+b-c)=2\cdot cos~(\frac{2a+2b}{2})\cdot cos~(\frac{2c}{c})\\\\\boxed{\boxed{cos~(a+b+c)+cos~(a+b-c)=2\cdot cos~(a+b)\cdot cos~c}}$

5 votes Thanks 4

Determine valor de x : a) cox = √2/2b) tg x = - √3c) 2. sen x = -1, para 0<x<2πd) 1 + co x = 0, para -π <x< πe) sen x= √2f) sec x = √2

Responda

Lista de comentários

Verified answer

Determine valor de x : a) cox = √2/2b) tg x = - √3c) 2. sen x = -1, para 0<x<2πd) 1 + co x = 0, para -π <x< πe) sen x= √2f) sec x = √2

Helpful Links

Helpful Social