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June 2021
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TRAVAIL BIEN PAYÉ ! Petit exercice sur les nombres complexes rémunéré avec 10 pts
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Akinarie
A) z1 + z2
= (1+3i) + (2-2i)
= 1+ 3i + 2 -2i
= 3+ i
b) 2 - 2i - 2(1-3i)
= 2-2i - 2 +6i
= 4i
c)(1+3i)(2-2i)
= 2 - 2i +6i -6i²
= -6i² -4i +2
d) (2-2i)²
= 2² -4i + 4i²
=4i²-4i+4
e) (1-(1+3i))(1+2-2i)
= (-3i)(3-2i)
= -9i+6i²
Je ne suis pas sûre de moi
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Bilss
Le C & le D sont faux mais merci quand même ;)
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= (1+3i) + (2-2i)
= 1+ 3i + 2 -2i
= 3+ i
b) 2 - 2i - 2(1-3i)
= 2-2i - 2 +6i
= 4i
c)(1+3i)(2-2i)
= 2 - 2i +6i -6i²
= -6i² -4i +2
d) (2-2i)²
= 2² -4i + 4i²
=4i²-4i+4
e) (1-(1+3i))(1+2-2i)
= (-3i)(3-2i)
= -9i+6i²
Je ne suis pas sûre de moi