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Patat1
@Patat1
May 2019
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TS sp maths
Bonjour, je dois trouver si l'entier de cette forme est pair ou impair:
1)
2)
3) Le premier entier > à 1000 pour la forme
J'ai trouvé 1) impair 2) pair et 3) k+16 mais je bloque
Merci
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scoladan
Verified answer
Bonjour,
1) 2k + 7 = 2k + 6 + 1 = 2(k + 3) + 1 donc impair
2) 7k + 12 = 7k + 7 + 5 = 7(k+1) + 5 donc impair
3) 9k + 31 > 1000
⇒ k > (1000 - 31)/9
⇔ k > 969/9
⇔ k > 107 + 6/9
⇒ k = 108
⇒ n = 9x108 + 31 = 1003
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Verified answer
Bonjour,1) 2k + 7 = 2k + 6 + 1 = 2(k + 3) + 1 donc impair
2) 7k + 12 = 7k + 7 + 5 = 7(k+1) + 5 donc impair
3) 9k + 31 > 1000
⇒ k > (1000 - 31)/9
⇔ k > 969/9
⇔ k > 107 + 6/9
⇒ k = 108
⇒ n = 9x108 + 31 = 1003