Verified answer

[tex] > \: resolucao \\ \\ \geqslant \: progressao \: \: aritmetica \\ \\ a1 = 5 \\ r = - 4 \\ \\ = = = = = = = = = = = = = = = = \\ \\ > \: o \: sexto \: termo \: da \: pa \\ \\ an = a1 + (n - 1)r \\ an = 5 + (6 - 1) - 4 \\ an = 5 + 5 \times ( - 4) \\ an = 5 + ( - 20) \\ an = 5 - 20 \\ an = - 15 \\ \\ \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \geqslant [/tex]

Explicação passo-a-passo:

a1=5

r= -4

a6=a1+5r

a6=5+5.-4

a6=5-20

a6= -15