Urgen svp aidez moi si vous pouvez detailler toutes les reponse merci: equation
1) 3x(au carre) −6x+3 = 0
3)x(au cube) −4x(au carre) +4x = 0
4) 4x(au carre) = 4x−1
1) 3x(au carre) −6x+3 = 0
3)x(au cube) −4x(au carre) +4x = 0
4) 4x(au carre) = 4x−1
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3(X-1)²=0 X-1=0 donc X=1
x(au cube) −4x(au carre) +4x = X(X²-4X+4)
X(X-2)(X-2)=0 donc X=0 OU X=2
4x²-4x+1 =
(2x-1)²=0
2x-1 = 0
2x = 1
x = 1/2
1) 3x² −6x+3 = 0
3(x²-2x+1) = 0
3(x-1)² = 0
x-1 = 0x = 1