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AlineDu85
@AlineDu85
January 2021
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(URGENT), bonsoir, j'aurais besoin d'aide pour ces exercices, c'est important et pressé... Merci à celui ou celle qui m'aidera !! :)
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scoladan
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Bonjour,
suite de ma première réponse
Ex 31)
C12H22O11 + 12O2 --> 12CO2 + 11H2O
m(C12H22O11) = 102,6 g
M(C12H22O11) = 12M(C) + 22M(H) + 11M(O)
= 12x12 + 22x1 + 11x16 = 342 g.mol^-1
==> n(C12H22O11) = m/M = 102,6/342 = 0,3 mol
D'après l'équation, n(O2) = 12 x n(C12H22O11)
==> n(O2) = 12 x 0,3 = 3,6 mol
M(O2) = 2 x M(O) = 2 x 16 = 32 g.mol^-1
==> m(O2) = 3,6 x 32 = 115,2 g
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Bonsoir, quelqu'un pourrait t-il m'aider s'il vous plait ? :)
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Bonsoir ! J'aurais besoin d'aide pour ces deux exercices s'il vous plait. Si quelqu'un pouvait m'aider se serait gentil... Merci :) !
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Bonjour,suite de ma première réponse
Ex 31)
C12H22O11 + 12O2 --> 12CO2 + 11H2O
m(C12H22O11) = 102,6 g
M(C12H22O11) = 12M(C) + 22M(H) + 11M(O)
= 12x12 + 22x1 + 11x16 = 342 g.mol^-1
==> n(C12H22O11) = m/M = 102,6/342 = 0,3 mol
D'après l'équation, n(O2) = 12 x n(C12H22O11)
==> n(O2) = 12 x 0,3 = 3,6 mol
M(O2) = 2 x M(O) = 2 x 16 = 32 g.mol^-1
==> m(O2) = 3,6 x 32 = 115,2 g