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Chocomilk9
@Chocomilk9
May 2019
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Urgent je suis en seconde et je dois faire un exercice de Maths. Est-ce que quelqu'un pourrait-il m'aider ? merci d'avance.
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nadiab
Bonsoir
1)
x
x+1
(x+1)²
-3(x+1)²
-3(x+1)²+5
f(-1)= -3((-1+1)²+5
f(-1)= 5
f(-1)= -3(-1-1)²+5
f(-1)= 7
2)
f(x)= -3(x+1)²+5
f(x)= -3(x²+2x+1)+5
f(x)= -3x²-6x-3+5
f(x)= -3x²-6x+2
3)
f(x)= -3x²-6x+2
α=-1
β= 5
Le α représente le x et le β représente le y, alors l'extremum sera (-1;5)
f(x)= 10
-3x²-6x+2= 10
-3x²-6x-8=0
Δ = -60, l'équation ne possède pas de solutions.
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1)
x
x+1
(x+1)²
-3(x+1)²
-3(x+1)²+5
f(-1)= -3((-1+1)²+5
f(-1)= 5
f(-1)= -3(-1-1)²+5
f(-1)= 7
2)
f(x)= -3(x+1)²+5
f(x)= -3(x²+2x+1)+5
f(x)= -3x²-6x-3+5
f(x)= -3x²-6x+2
3)
f(x)= -3x²-6x+2
α=-1
β= 5
Le α représente le x et le β représente le y, alors l'extremum sera (-1;5)
f(x)= 10
-3x²-6x+2= 10
-3x²-6x-8=0
Δ = -60, l'équation ne possède pas de solutions.