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maycongato7
@maycongato7
July 2022
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valendo 20 pontos
obs: quero o calculo
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Geraldo5
É só colocar f(x) onde há x na função g(x) assim:
g(x)= -x²+3
g[f(x)]= -[f(x)]²+3
g[f(x)]= -(2x+1)²+3
g[f(x)]= -(4x²+4x+1)+3
g[f(x)]= -4x²-4x-1+3
g[f(x)]= -4x²-4x+2
Letra B. =D
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g(x)= -x²+3
g[f(x)]= -[f(x)]²+3
g[f(x)]= -(2x+1)²+3
g[f(x)]= -(4x²+4x+1)+3
g[f(x)]= -4x²-4x-1+3
g[f(x)]= -4x²-4x+2
Letra B. =D