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Drew21
@Drew21
April 2019
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Voilà la photo de l'exercice :)
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Bonsoir
Pythagore dans le triangle AHB rectangle en H.
AH² + HB² = AB²
2,1² + HB² = 7,5²
4,41 + HB² = 56,25
HB² = 56,25 - 4,41
HB² = 51,84
Le chaton se trouve à 7,2 m au-dessus du sol.
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Pythagore dans le triangle AHB rectangle en H.
AH² + HB² = AB²
2,1² + HB² = 7,5²
4,41 + HB² = 56,25
HB² = 56,25 - 4,41
HB² = 51,84
Le chaton se trouve à 7,2 m au-dessus du sol.