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cloe3112
@cloe3112
January 2021
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vous pouvez m’aider svp, je dois rendre sa dans pas longtemps et je comprend rien juste donner l’es méthode à faire et je fais les calculs
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taalbabachir
EX1
soit A = (3 x + 7)(6 - 5 x) + (6 - 5 x)²
4. Développer et réduire A
A = (3 x + 7)(6 - 5 x) + (6 - 5 x)²
= 18 x - 15 x² + 42 - 35 x + 36 - 60 x + 25 x²
= 10 x² - 77 x + 78
5. Factoriser A
A = (3 x + 7)(6 - 5 x) + (6 - 5 x)²
= (6 - 5 x)[3 x + 7 + 6 - 5 x]
= (6 - 5 x)(13 - 2 x)
6. Calculer A pour x = 3 puis pour x = 1/2
A = (6 - 5 x)(13 - 2 x)
= (6 - 5*3)(13 - 2*3)
= - 9*7 = - 63
A = 10 x² - 77 x + 78
= 10 (1/2)² - 77(1/2) + 78
= 10/4 - 77/2 + 78
= 5/2 - 77/2 + 78
= - 72/2 + 78
= - 36 + 78 = 42
EX2
tan 22° = 40/d1 ⇒ d1 = 40/tan 22° = 40/0.404 = 99 m
tan 16° = 40/D ⇒ D = 40/tan 16° = 40/0.287 = 139.37 m
la distance AB = D - d1 = 139.37 - 99 = 40.37 m
Bonus
une pièce rectangulaire dont la longueur L = 2 x l
A = 24.5 = L x l = 2 x l² ⇒ l² = 24.5/2 = 12.25 ⇒ l = √12.25 = 3.5 m
L = 2 x 3.5 = 7 m
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cloe3112
wow merci énormément je sais pas quoi dire pour tout ca
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Lista de comentários
soit A = (3 x + 7)(6 - 5 x) + (6 - 5 x)²
4. Développer et réduire A
A = (3 x + 7)(6 - 5 x) + (6 - 5 x)²
= 18 x - 15 x² + 42 - 35 x + 36 - 60 x + 25 x²
= 10 x² - 77 x + 78
5. Factoriser A
A = (3 x + 7)(6 - 5 x) + (6 - 5 x)²
= (6 - 5 x)[3 x + 7 + 6 - 5 x]
= (6 - 5 x)(13 - 2 x)
6. Calculer A pour x = 3 puis pour x = 1/2
A = (6 - 5 x)(13 - 2 x)
= (6 - 5*3)(13 - 2*3)
= - 9*7 = - 63
A = 10 x² - 77 x + 78
= 10 (1/2)² - 77(1/2) + 78
= 10/4 - 77/2 + 78
= 5/2 - 77/2 + 78
= - 72/2 + 78
= - 36 + 78 = 42
EX2
tan 22° = 40/d1 ⇒ d1 = 40/tan 22° = 40/0.404 = 99 m
tan 16° = 40/D ⇒ D = 40/tan 16° = 40/0.287 = 139.37 m
la distance AB = D - d1 = 139.37 - 99 = 40.37 m
Bonus
une pièce rectangulaire dont la longueur L = 2 x l
A = 24.5 = L x l = 2 x l² ⇒ l² = 24.5/2 = 12.25 ⇒ l = √12.25 = 3.5 m
L = 2 x 3.5 = 7 m