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Siazzle
@Siazzle
April 2019
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AIDEZ MOI SVP C TRÈS URGENT !!
Résoudre les inéquations :
x3 < 4x
9x > 4/x
x <= x2
Merci à tous ceux qui le feront !
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Commentaires (1)
x³ < 4x
x³-4x<0
x(x²-4)<0
x(x-2)(x+2)<0
tab de signes
donc S=]-∞;-2[ U ]0;2[
9x > 4/x
(9x²-4)/x>0
(3x-2)(3x+2)/x>0
tab de signes
donc S=]-2/3;0[ U ]2/3;+∞[
x ≤ x²
x-x²≤0
x(1-x)≤0
tab de signes
donc S=]-∞;0] U [1;+∞[
1 votes
Thanks 1
siazzle
merci beaucoup de ton aide
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x³-4x<0
x(x²-4)<0
x(x-2)(x+2)<0
tab de signes
donc S=]-∞;-2[ U ]0;2[
9x > 4/x
(9x²-4)/x>0
(3x-2)(3x+2)/x>0
tab de signes
donc S=]-2/3;0[ U ]2/3;+∞[
x ≤ x²
x-x²≤0
x(1-x)≤0
tab de signes
donc S=]-∞;0] U [1;+∞[