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arthur275
@arthur275
October 2020
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(x+8)(x-8) + (x+3)(x-1)
ajudem
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Heberwagner
(a + b).(a - b) = a² + b², logo (x+8)(x-8) = x² + 16, então:
x² + 16 +
(x+3)(x-1) =
x² + 16 + x² - x + 3x - 3 =
2x² + 2x + 13.
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Thanks 3
arthur275
ajudou
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x² + 16 + (x+3)(x-1) =
x² + 16 + x² - x + 3x - 3 =
2x² + 2x + 13.