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Arthur275
@Arthur275
May 2020
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Equaçoes literais do 1° grau
a) 3x + a = x + 5a - 6
b) a(x-2) = 2(x+5), para a
2
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Verified answer
a) 3x + a = x + 5a - 6
3x - x = 5a - a - 6
2x = 4a - 6
2x = 2(a - 3)
x =
2(a - 3)
simplificando 2 do numerador com o 2 do denominador
2
x= a - 3
b) a(x-2) = 2(x+5)
a = 2
(x + 5)
x - 2
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Verified answer
a) 3x + a = x + 5a - 63x - x = 5a - a - 6
2x = 4a - 6
2x = 2(a - 3)
x = 2(a - 3) simplificando 2 do numerador com o 2 do denominador
2
x= a - 3
b) a(x-2) = 2(x+5)
a = 2(x + 5)
x - 2