Bonjour, je dois mettre sous forme d'un quotient mais je suis bloqué à la 2ème. Pouvez-vous m'aider SVP? Merci d'avance f(x) = x-2+ 3/(x-4)
g(x) =1/x² - 6/(x+2)
h(x) = (2x-1)/(x+2) + x/(x-3)
h(x) = 5 - (x+3)/(x²-25) - x²/(x+5)
j'ai fait f(x) = x-2+ 3/(x-4) = [(x-2)(x+4)+3]/ x²(x+2) = (x²-4x-2x+8+3 )/(x-4) = (x² -6x+11)/(x-4)
g(x) =g(x) =1/x² - 6/(x+2) = (x+2 -6 x²)/(x²(x+2)) = (-6x²+x+2)/x²(x+2).. là, je bloque
g(x) =1/x² - 6/(x+2)
h(x) = (2x-1)/(x+2) + x/(x-3)
h(x) = 5 - (x+3)/(x²-25) - x²/(x+5)
j'ai fait f(x) = x-2+ 3/(x-4) = [(x-2)(x+4)+3]/ x²(x+2) = (x²-4x-2x+8+3 )/(x-4) = (x² -6x+11)/(x-4)
g(x) =g(x) =1/x² - 6/(x+2) = (x+2 -6 x²)/(x²(x+2)) = (-6x²+x+2)/x²(x+2).. là, je bloque
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