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Moussaillon5946
@Moussaillon5946
May 2019
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Bonjour
j'ai trouvé sin x = cos (π/2 - x) alors
pourquoi sin 2x = cos (π/2 - x)
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ProfdeMaths1
Verified answer
sin x = cos (π/2 - x)
donc sin(2x)=2.sin(x)cos(x)
=2.cos(π/2-x).cos(x)
=2*1/2(cos(π/2-x+x)+cos(π/2-x-x))
=cos(π/2)+cos(π/2-2x)
=
cos(π/2-2x)
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ProfdeMaths1
non tu n'as pas compris ma correction...
ProfdeMaths1
cos(a)=cos(b) implique a=b ou a=-b
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Verified answer
sin x = cos (π/2 - x)donc sin(2x)=2.sin(x)cos(x)
=2.cos(π/2-x).cos(x)
=2*1/2(cos(π/2-x+x)+cos(π/2-x-x))
=cos(π/2)+cos(π/2-2x)
=cos(π/2-2x)