Bonjour
j'ai trouvé sin x = cos (π/2 - x) alors
pourquoi sin 2x = cos (π/2 - x)
j'ai trouvé sin x = cos (π/2 - x) alors
pourquoi sin 2x = cos (π/2 - x)
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sin x = cos (π/2 - x)donc sin(2x)=2.sin(x)cos(x)
=2.cos(π/2-x).cos(x)
=2*1/2(cos(π/2-x+x)+cos(π/2-x-x))
=cos(π/2)+cos(π/2-2x)
=cos(π/2-2x)