Verified answer

Resposta:

5

Explicação passo a passo:

[tex]x^{\frac{a}{b} }=\sqrt[b]{x^a}[/tex]

então

[tex]27^{\frac{1}{3} }=\sqrt[3]{27^1}=3[/tex]

[tex]4^{\frac{1}{2}}=\sqrt{4} =2[/tex]

2 + 3 = 5

[tex](27)^{\frac{1}{3} } + (4)^{-\frac{1}{2} }[/tex]

[tex]\sqrt[3]{27} + (\frac{1}{4})^{\frac{1}{2} }[/tex]

[tex]3+\sqrt{\frac{1}{4} }[/tex]

[tex]3+\frac{1}{2}[/tex]

[tex]\frac{6+1}{2} = \frac{7}{2}[/tex]