Verified answer

Bonsoir,

[tex]\frac{3}{2}-\frac{41}{8}+\frac{9}{2}= \frac{3*4}{2*4}-\frac{41}{8}+\frac{9*4}{2*4}=\frac{12}{8}-\frac{41}{8}+\frac{36}{8}=\frac{7}{8}[/tex]

[tex]-\frac{23}{28}+9=-\frac{23}{28} +\frac{9*28}{28}=-\frac{23}{28}+\frac{252}{28}=\frac{229}{28}[/tex]