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HopeAndDignity
@HopeAndDignity
May 2019
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Bonjour ! Pouvez vous m'aider ? Merci beaucoup !
Résoudre l'inéquation : x + 15 (supérieur ou égal à) 2/3 (x + 27)
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maudmarine
Verified answer
Bonjour,
x + 15 ≥ 2/3 (x + 27)
x + 15 ≥ 2/3x + 54/3
x + 15 ≥ 2/3x + 18
x - 2/3x ≥ 18 - 15
3/3x - 2/3x ≥ 3
1/3x ≥ 9/3
x ≥ 3
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Verified answer
Bonjour,x + 15 ≥ 2/3 (x + 27)
x + 15 ≥ 2/3x + 54/3
x + 15 ≥ 2/3x + 18
x - 2/3x ≥ 18 - 15
3/3x - 2/3x ≥ 3
1/3x ≥ 9/3
x ≥ 3