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Apexpredator
@Apexpredator
April 2019
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Résoudre inéquations :
a) (2x+3)(x-5)
≧ 0
b) (x+5)(-3x+1)
≧ 0
c) 3x-5/-x+2
≦ 0
g) 5/x+2 < 2/x+1
f) (2x+1)(-5x+2)/3x+7
≦ 0
Merci beacoup
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On effectue un tableau de signes à chaque fois :
a) (2x+3)(x-5)
≧ 0
S=]-inf;-3/2;] U [5;+inf[
b) (x+5)(-3x+1)
≧ 0
S=[-5;1/3]
c) (3x-5)/(-x+2)
≦ 0
S=]-inf;5/3] U [2;+inf[
g) 5/(x+2) < 2/(x+1)
S=]-inf;-2[ U ]-1;-1/3[
f) (2x+1)(-5x+2)/(3x+7)
≦ 0
S=[-7/3;-1/2] U [2/5;+inf[
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a) (2x+3)(x-5) ≧ 0
S=]-inf;-3/2;] U [5;+inf[
b) (x+5)(-3x+1) ≧ 0
S=[-5;1/3]
c) (3x-5)/(-x+2) ≦ 0
S=]-inf;5/3] U [2;+inf[
g) 5/(x+2) < 2/(x+1)
S=]-inf;-2[ U ]-1;-1/3[
f) (2x+1)(-5x+2)/(3x+7) ≦ 0
S=[-7/3;-1/2] U [2/5;+inf[