Verified answer

Resposta:

Para resolver é simples, devemos organizar em forma de fatoração e decompor os números por números primos, por exemplos; 2, 3, 5, 7...

a) 3, 18 | 2

3, 9 | 3

1, 3 | 3

1, 1 | 1

MMC = 2 × 3 × 3 = 18

b) 20, 30 | 2

10, 15 | 2

5, 15 | 3

5, 5 | 5

1, 1 | 1

MMC = 2 x 2 × 3 × 5 = 60

c) 42, 24 | 2

21, 12 | 2

21, 6 | 2

21, 3 | 3

7, 1 | 7

1, 1 | 1

MMC = 2 × 2 × 2 × 3 × 7 = 168

d) 56, 100 | 2

28, 50 | 2

14, 25 | 2

7, 25 | 5

7, 5 | 5

7, 1 | 7

1, 1 | 1

MMC = 2 × 2 × 2 × 5 × 5 × 7 = 1400

e) 26, 36 | 2

13, 18 | 2

13, 9 | 3

13, 3 | 3

13, 1 | 13

1, 1 | 1

MMC = 2 × 2 × 3 × 3 × 13 = 468

f) 32, 58 | 2

16, 29 | 2

8, 29 | 2

4, 29 | 2

2, 29 | 2

1, 29 | 29

1, 1 | 1

MMC = 2 × 2 × 2 × 2 × 2 × 29 = 928

g) 52, 120 | 2

26, 60 | 2

13, 30 | 2

13, 15 | 3

13, 5 | 5

13, 1 | 13

1, 1 | 1

MMC = 2 × 2 × 2 × 3 × 5 × 13 = 1560

h) 18, 72 | 2

9, 36 | 2

9, 18 | 2

9, 9 | 3

3, 3 | 3

1, 1 | 1

MMC = 2 × 2 × 2 × 3 × 3 = 72

i) 66, 82 | 2

33, 41 | 3

11, 41 | 11

1, 41 | 41

1, 1 | 1

MMC = 2 × 3 × 11 × 41 = 2706

j) 112, 160 | 2

56, 80 | 2

28, 40 | 2

14, 20 | 2

7, 10 | 2

7, 5 | 5

7, 1 | 7

1, 1 | 1

MMC = 2 × 2 × 2 × 2 × 2 × 5 × 7 = 1120

k) 130, 70 | 2

65, 35 | 5

13, 7 | 7

13, 1 | 13

1, 1 | 1

MMC = 2 × 5 × 7 × 13 = 910

l) 112, 62 | 2

56, 31 | 2

28, 31 | 2

14, 31 | 2

7, 31 | 7

1, 31 | 31

1, 1 | 1

MMC = 2 × 2 × 2 × 2 × 7 × 31 = 3472

Resposta:

A) 18

B) 60

C) 168

D) 1400

E) 468

F) 928

G) 1560

H) 72

I) 2706

J) 1120

K) 970

L) 496