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Zanouba2
@Zanouba2
May 2019
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Bns aide moi svp
1-soient A(22π/3) ; B(-35π/6) ; C(39π/4)
trois pts sur un cercle trigonométrique
calculer les mesures et les mesures principales des angles orientés suivants
(OA; OB) ,( OB; OC) , (OC ; OA)
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croisierfamily
22π/3 = 18π/3 + 4π/3 = 4π/3 = 240°
-35π/6 = -36π/6 + π/6 = π/6 = 30°
39π/4 = 32π/4 + 7π/4 = 7π/4 = 315°
angles (OA;OB) = (360° - 240°) + 30° = 150° = 5π/6
(OB;OC) = 315° - 30° = 285 ° = 19π/12
(OC;OA) = (360° - 315°) + 240° = 285° = 19π/12 aussi !
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Thanks 1
zanouba2
mercii bc
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-35π/6 = -36π/6 + π/6 = π/6 = 30°
39π/4 = 32π/4 + 7π/4 = 7π/4 = 315°
angles (OA;OB) = (360° - 240°) + 30° = 150° = 5π/6
(OB;OC) = 315° - 30° = 285 ° = 19π/12
(OC;OA) = (360° - 315°) + 240° = 285° = 19π/12 aussi !