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fgq99Esthefany
@fgq99Esthefany
March 2022
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(1/5) elevado a (3x-2)>1
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claudiasoueu
(1/5)^(3x-2) > (1/5)° lembre que todo nº elevado a 0 dá sempre 1
3x - 2 > 0
3x>2
x>2/3
3 votes
Thanks 5
fgq99Esthefany
responde a que vou postar agora
moreninha17
Acho que é
5^(2x² -3x -2) =1 ......(multiplicando ambos os lados por 5 para igualar as bases.):
5¹*5^(2x² -3x -2) =1*5¹ .... X^n * X^m = X^(n+m)
5^(2x² -3x -2+1) = 5¹
5^(2x² -3x -1) = 5¹ ... (equação exponencial)
2x²-3x-1 = 1
2x²-3x-2 = 0 ...(equação do 2º grau)
Δ = b²-4*a*c
Δ = (-3)²-4*2*(-2)
Δ = 9+16
Δ = 25
x = (-b±√Δ)/2*a
x = (-(-3)±√25)/2*2
x' = (3+5)/4
x' = 8/4
x' = 2
x'' = (3-5)/4
x'' = -2/4
x'' = -1/2
S{2, -1/2}
0 votes
Thanks 1
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3x - 2 > 0
3x>2
x>2/3
5¹*5^(2x² -3x -2) =1*5¹ .... X^n * X^m = X^(n+m)
5^(2x² -3x -2+1) = 5¹
5^(2x² -3x -1) = 5¹ ... (equação exponencial)
2x²-3x-1 = 1
2x²-3x-2 = 0 ...(equação do 2º grau)
Δ = b²-4*a*c
Δ = (-3)²-4*2*(-2)
Δ = 9+16
Δ = 25
x = (-b±√Δ)/2*a
x = (-(-3)±√25)/2*2
x' = (3+5)/4
x' = 8/4
x' = 2
x'' = (3-5)/4
x'' = -2/4
x'' = -1/2
S{2, -1/2}