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Dianebtz
@Dianebtz
April 2019
1
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Soit A=3√15 x2√35-2√84-7√105/
√5
Ecrire A sous la forme a
√b ou a et b sont deux entiers naturels a déterminer .
Le détail des différents calculs devra figurer sur votre feuille.
Merci d'avance !
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caro67000
Soit A=3√15 x2√35-2√84-7√105/
√5
A= 6 √15*35 - 2√4*21- 7 √21*5/√5
A = 6 √525 - 4 √21 - 7 √21
A = 6 √25*21 - 4 √21 - 7 √21
A = 30 √21 - 4 √21 - 7 √21
A = 19 √21
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caro67000
oui?
caro67000
lequel?
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A= 6 √15*35 - 2√4*21- 7 √21*5/√5
A = 6 √525 - 4 √21 - 7 √21
A = 6 √25*21 - 4 √21 - 7 √21
A = 30 √21 - 4 √21 - 7 √21
A = 19 √21