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HopeAndDignity
@HopeAndDignity
May 2019
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Bonjour, pouvez-vous m'aider sur cette exo de Maths, s'il vous plaît ?
Merci !
X =(1/3 +5/6a)
X =
Y = (
b – 1)
Y =
Z = (c + √7) (c - √7)
Z =
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aymanemaysae
Verified answer
Bonjour ;
X = (1/3 + 5/6 a)²
= (1/3)² + 2 * 1/3 * 5/6 a + (5/6 a)²
= 1/9 + 5/9 a + 25/36 a² .
Y = (10^3 b – 1)²
= (10^3 b)² - 2 * 10^3 b + 1
= 10^6 b² - 2 * 10^3 b + 1
Z = (c + √7) (c - √7)
= c² - (√7)²
= c² - 7
Z =
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isapaul
Bonjour il me semble que y = 10^6b² - 2 * 10^3b + 1
nini999
Bonjour :
X = (1/3 + 5/6a)²
(1/3 + 5/6a)² il prend la forme de (a+b)² = a²+2ab+b²
Alors :
X = (1/3)² + 2 × 1/3 × 5/6a + (5/6a)²
X = 1/9 + 5/9a + 25/36a²
Y = (10³b - 1)²
(10³b - 1)² il prend la forme de (a-b)²=a²-2ab+b²
Alors :
(10³b)² - 2 × 10³b × 1 + 1²
10⁶b² - 2 × 10³b + 1²
Z = (c + √7)(c - √7)
(c + √7)(c - √7) il prend la forme de (a+b)(a-b) = a²-2b²
Alors :
Z = (c)² + (√7)²
Z = c² + 7
J’espère t'avoir t'aider
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Thanks 0
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Verified answer
Bonjour ;X = (1/3 + 5/6 a)²
= (1/3)² + 2 * 1/3 * 5/6 a + (5/6 a)²
= 1/9 + 5/9 a + 25/36 a² .
Y = (10^3 b – 1)²
= (10^3 b)² - 2 * 10^3 b + 1
= 10^6 b² - 2 * 10^3 b + 1
Z = (c + √7) (c - √7)
= c² - (√7)²
= c² - 7
Z =
X = (1/3 + 5/6a)²
(1/3 + 5/6a)² il prend la forme de (a+b)² = a²+2ab+b²
Alors :
X = (1/3)² + 2 × 1/3 × 5/6a + (5/6a)²
X = 1/9 + 5/9a + 25/36a²
Y = (10³b - 1)²
(10³b - 1)² il prend la forme de (a-b)²=a²-2ab+b²
Alors :
(10³b)² - 2 × 10³b × 1 + 1²
10⁶b² - 2 × 10³b + 1²
Z = (c + √7)(c - √7)
(c + √7)(c - √7) il prend la forme de (a+b)(a-b) = a²-2b²
Alors :
Z = (c)² + (√7)²
Z = c² + 7
J’espère t'avoir t'aider